((-7x+23)/(x-3)^2)+(4/(x-3))+1=0

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Solution for ((-7x+23)/(x-3)^2)+(4/(x-3))+1=0 equation:


D( x )

x-3 = 0

(x-3)^2 = 0

x-3 = 0

x-3 = 0

x-3 = 0 // + 3

x = 3

(x-3)^2 = 0

(x-3)^2 = 0

x-3 = 0 // + 3

x = 3

x in (-oo:3) U (3:+oo)

(23-7*x)/((x-3)^2)+4/(x-3)+1 = 0

(23-7*x)/((x-3)^2)+(4*(x-3))/((x-3)^2)+(1*(x-3)^2)/((x-3)^2) = 0

4*(x-3)+1*(x-3)^2-7*x+23 = 0

x^2-3*x-6*x+9+11 = 0

x^2-9*x+20 = 0

x^2-9*x+20 = 0

x^2-9*x+20 = 0

DELTA = (-9)^2-(1*4*20)

DELTA = 1

DELTA > 0

x = (1^(1/2)+9)/(1*2) or x = (9-1^(1/2))/(1*2)

x = 5 or x = 4

(x-4)*(x-5) = 0

((x-4)*(x-5))/((x-3)^2) = 0

((x-4)*(x-5))/((x-3)^2) = 0 // * (x-3)^2

(x-4)*(x-5) = 0

( x-4 )

x-4 = 0 // + 4

x = 4

( x-5 )

x-5 = 0 // + 5

x = 5

x in { 4, 5 }

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